x-16x^(1/2)-512

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Solution for x-16x^(1/2)-512 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x-(16*x^(1/2))-512 = 0

x-16*x^(1/2)-512 = 0

t_1 = x^(1/2)

1*t_1^2-16*t_1^1-512 = 0

t_1^2-16*t_1-512 = 0

DELTA = (-16)^2-(-512*1*4)

DELTA = 2304

DELTA > 0

t_1 = (2304^(1/2)+16)/(1*2) or t_1 = (16-2304^(1/2))/(1*2)

t_1 = 32 or t_1 = -16

t_1 = -16

x^(1/2)+16 = 0

1*x^(1/2) = -16 // : 1

x^(1/2) = -16

( -16 < 0 i 1/2 in (0:1) ) => x naleu017Cy do O

t_1 = 32

x^(1/2)-32 = 0

1*x^(1/2) = 32 // : 1

x^(1/2) = 32

x^(1/2) = 32 // ^ 2

x = 1024

x = 1024

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